-2(y+3)=4y-8+6(2y+2)

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Solution for -2(y+3)=4y-8+6(2y+2) equation: 



-2(y+3)=4y-8+6(2y+2)

We move all terms to the left:

-2(y+3)-(4y-8+6(2y+2))=0

We multiply parentheses

-2y-(4y-8+6(2y+2))-6=0



We calculate terms in parentheses: -(4y-8+6(2y+2)), so:

4y-8+6(2y+2)

determiningTheFunctionDomain
4y+6(2y+2)-8

We multiply parentheses

4y+12y+12-8

We add all the numbers together, and all the variables

16y+4

Back to the equation:

-(16y+4)



We get rid of parentheses

-2y-16y-4-6=0

We add all the numbers together, and all the variables

-18y-10=0

We move all terms containing y to the left, all other terms to the right

-18y=10

y=10/-18

y=-5/9

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