-2(y+4)=y-7+4(3y+1)

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Solution for -2(y+4)=y-7+4(3y+1) equation: 



-2(y+4)=y-7+4(3y+1)

We move all terms to the left:

-2(y+4)-(y-7+4(3y+1))=0

We multiply parentheses

-2y-(y-7+4(3y+1))-8=0



We calculate terms in parentheses: -(y-7+4(3y+1)), so:

y-7+4(3y+1)

determiningTheFunctionDomain
y+4(3y+1)-7

We multiply parentheses

y+12y+4-7

We add all the numbers together, and all the variables

13y-3

Back to the equation:

-(13y-3)



We get rid of parentheses

-2y-13y+3-8=0

We add all the numbers together, and all the variables

-15y-5=0

We move all terms containing y to the left, all other terms to the right

-15y=5

y=5/-15

y=-1/3

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