-2(y+5)=8y-2+2(2y+5)

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Solution for -2(y+5)=8y-2+2(2y+5) equation:



-2(y+5)=8y-2+2(2y+5)
We move all terms to the left:
-2(y+5)-(8y-2+2(2y+5))=0
We multiply parentheses
-2y-(8y-2+2(2y+5))-10=0
We calculate terms in parentheses: -(8y-2+2(2y+5)), so:
8y-2+2(2y+5)
determiningTheFunctionDomain 8y+2(2y+5)-2
We multiply parentheses
8y+4y+10-2
We add all the numbers together, and all the variables
12y+8
Back to the equation:
-(12y+8)
We get rid of parentheses
-2y-12y-8-10=0
We add all the numbers together, and all the variables
-14y-18=0
We move all terms containing y to the left, all other terms to the right
-14y=18
y=18/-14
y=-1+2/7

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