-2(y+5)=8y-6+2(4y+1)

Solution for -2(y+5)=8y-6+2(4y+1) equation:

-2(y+5)=8y-6+2(4y+1)

We move all terms to the left:

-2(y+5)-(8y-6+2(4y+1))=0

We multiply parentheses

-2y-(8y-6+2(4y+1))-10=0


We calculate terms in parentheses: -(8y-6+2(4y+1)), so:

8y-6+2(4y+1)

determiningTheFunctionDomain
8y+2(4y+1)-6

We multiply parentheses

8y+8y+2-6

We add all the numbers together, and all the variables

16y-4

Back to the equation:

-(16y-4)


We get rid of parentheses

-2y-16y+4-10=0

We add all the numbers together, and all the variables

-18y-6=0

We move all terms containing y to the left, all other terms to the right

-18y=6

y=6/-18

y=-1/3