-2(y-1)+5y=3(y+1)-2

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Solution for -2(y-1)+5y=3(y+1)-2 equation: 



-2(y-1)+5y=3(y+1)-2

We move all terms to the left:

-2(y-1)+5y-(3(y+1)-2)=0

We add all the numbers together, and all the variables

5y-2(y-1)-(3(y+1)-2)=0

We multiply parentheses

5y-2y-(3(y+1)-2)+2=0



We calculate terms in parentheses: -(3(y+1)-2), so:

3(y+1)-2

We multiply parentheses

3y+3-2

We add all the numbers together, and all the variables

3y+1

Back to the equation:

-(3y+1)



We add all the numbers together, and all the variables

3y-(3y+1)+2=0

We get rid of parentheses

3y-3y-1+2=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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