-2(y-1)=4y-(y+-2)

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Solution for -2(y-1)=4y-(y+-2) equation: 



-2(y-1)=4y-(y+-2)

We move all terms to the left:

-2(y-1)-(4y-(y+-2))=0

We add all the numbers together, and all the variables

-2(y-1)-(4y-(y-2))=0

We multiply parentheses

-2y-(4y-(y-2))+2=0



We calculate terms in parentheses: -(4y-(y-2)), so:

4y-(y-2)

We get rid of parentheses

4y-y+2

We add all the numbers together, and all the variables

3y+2

Back to the equation:

-(3y+2)



We get rid of parentheses

-2y-3y-2+2=0

We add all the numbers together, and all the variables

-5y=0

y=0/-5

y=0

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