-2(y-10)=3(2y+4)

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Solution for -2(y-10)=3(2y+4) equation: 



-2(y-10)=3(2y+4)

We move all terms to the left:

-2(y-10)-(3(2y+4))=0

We multiply parentheses

-2y-(3(2y+4))+20=0



We calculate terms in parentheses: -(3(2y+4)), so:

3(2y+4)

We multiply parentheses

6y+12

Back to the equation:

-(6y+12)



We get rid of parentheses

-2y-6y-12+20=0

We add all the numbers together, and all the variables

-8y+8=0

We move all terms containing y to the left, all other terms to the right

-8y=-8

y=-8/-8

y=1

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