-2(y-2)=4y-(y+2)

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Solution for -2(y-2)=4y-(y+2) equation: 



-2(y-2)=4y-(y+2)

We move all terms to the left:

-2(y-2)-(4y-(y+2))=0

We multiply parentheses

-2y-(4y-(y+2))+4=0



We calculate terms in parentheses: -(4y-(y+2)), so:

4y-(y+2)

We get rid of parentheses

4y-y-2

We add all the numbers together, and all the variables

3y-2

Back to the equation:

-(3y-2)



We get rid of parentheses

-2y-3y+2+4=0

We add all the numbers together, and all the variables

-5y+6=0

We move all terms containing y to the left, all other terms to the right

-5y=-6

y=-6/-5

y=1+1/5

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