-2(y-2)=5(2-y)

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Solution for -2(y-2)=5(2-y) equation: 



-2(y-2)=5(2-y)

We move all terms to the left:

-2(y-2)-(5(2-y))=0

We add all the numbers together, and all the variables

-2(y-2)-(5(-1y+2))=0

We multiply parentheses

-2y-(5(-1y+2))+4=0



We calculate terms in parentheses: -(5(-1y+2)), so:

5(-1y+2)

We multiply parentheses

-5y+10

Back to the equation:

-(-5y+10)



We get rid of parentheses

-2y+5y-10+4=0

We add all the numbers together, and all the variables

3y-6=0

We move all terms containing y to the left, all other terms to the right

3y=6

y=6/3

y=2

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