-2(y-3)=4(y-12)

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Solution for -2(y-3)=4(y-12) equation: 



-2(y-3)=4(y-12)

We move all terms to the left:

-2(y-3)-(4(y-12))=0

We multiply parentheses

-2y-(4(y-12))+6=0



We calculate terms in parentheses: -(4(y-12)), so:

4(y-12)

We multiply parentheses

4y-48

Back to the equation:

-(4y-48)



We get rid of parentheses

-2y-4y+48+6=0

We add all the numbers together, and all the variables

-6y+54=0

We move all terms containing y to the left, all other terms to the right

-6y=-54

y=-54/-6

y=+9

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