-2(y-3y)+4=-3(4y-y)+1+12y

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Solution for -2(y-3y)+4=-3(4y-y)+1+12y equation: 



-2(y-3y)+4=-3(4y-y)+1+12y

We move all terms to the left:

-2(y-3y)+4-(-3(4y-y)+1+12y)=0

We add all the numbers together, and all the variables

-2(-2y)-(-3(+3y)+1+12y)+4=0

We multiply parentheses

4y-(-3(+3y)+1+12y)+4=0



We calculate terms in parentheses: -(-3(+3y)+1+12y), so:

-3(+3y)+1+12y

determiningTheFunctionDomain
-3(+3y)+12y+1

We add all the numbers together, and all the variables

12y-3(+3y)+1

We multiply parentheses

12y-9y+1

We add all the numbers together, and all the variables

3y+1

Back to the equation:

-(3y+1)



We get rid of parentheses

4y-3y-1+4=0

We add all the numbers together, and all the variables

y+3=0

We move all terms containing y to the left, all other terms to the right

y=-3

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