-2(y-3y)+7=-3(6y-y)+2+18y

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Solution for -2(y-3y)+7=-3(6y-y)+2+18y equation: 



-2(y-3y)+7=-3(6y-y)+2+18y

We move all terms to the left:

-2(y-3y)+7-(-3(6y-y)+2+18y)=0

We add all the numbers together, and all the variables

-2(-2y)-(-3(+5y)+2+18y)+7=0

We multiply parentheses

4y-(-3(+5y)+2+18y)+7=0



We calculate terms in parentheses: -(-3(+5y)+2+18y), so:

-3(+5y)+2+18y

determiningTheFunctionDomain
-3(+5y)+18y+2

We add all the numbers together, and all the variables

18y-3(+5y)+2

We multiply parentheses

18y-15y+2

We add all the numbers together, and all the variables

3y+2

Back to the equation:

-(3y+2)



We get rid of parentheses

4y-3y-2+7=0

We add all the numbers together, and all the variables

y+5=0

We move all terms containing y to the left, all other terms to the right

y=-5

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