-2(y-4)+3(3y-2)=-2-(6y-2)

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Solution for -2(y-4)+3(3y-2)=-2-(6y-2) equation: 



-2(y-4)+3(3y-2)=-2-(6y-2)

We move all terms to the left:

-2(y-4)+3(3y-2)-(-2-(6y-2))=0

We multiply parentheses

-2y+9y-(-2-(6y-2))+8-6=0



We calculate terms in parentheses: -(-2-(6y-2)), so:

-2-(6y-2)

determiningTheFunctionDomain
-(6y-2)-2

We get rid of parentheses

-6y+2-2

We add all the numbers together, and all the variables

-6y

Back to the equation:

-(-6y)



We add all the numbers together, and all the variables

7y-(-6y)+2=0

We get rid of parentheses

7y+6y+2=0

We add all the numbers together, and all the variables

13y+2=0

We move all terms containing y to the left, all other terms to the right

13y=-2

y=-2/13

y=-2/13

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