-2(y-4)=y-4+3y

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Solution for -2(y-4)=y-4+3y equation: 



-2(y-4)=y-4+3y

We move all terms to the left:

-2(y-4)-(y-4+3y)=0

We add all the numbers together, and all the variables

-2(y-4)-(4y-4)=0

We multiply parentheses

-2y-(4y-4)+8=0

We get rid of parentheses

-2y-4y+4+8=0

We add all the numbers together, and all the variables

-6y+12=0

We move all terms containing y to the left, all other terms to the right

-6y=-12

y=-12/-6

y=+2

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