-2(y-4)=y-4+3y

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Solution for -2(y-4)=y-4+3y equation:



-2(y-4)=y-4+3y
We move all terms to the left:
-2(y-4)-(y-4+3y)=0
We add all the numbers together, and all the variables
-2(y-4)-(4y-4)=0
We multiply parentheses
-2y-(4y-4)+8=0
We get rid of parentheses
-2y-4y+4+8=0
We add all the numbers together, and all the variables
-6y+12=0
We move all terms containing y to the left, all other terms to the right
-6y=-12
y=-12/-6
y=+2

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