-2(y-4y)+4=-6(2y-y)+3+11y

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Solution for -2(y-4y)+4=-6(2y-y)+3+11y equation: 



-2(y-4y)+4=-6(2y-y)+3+11y

We move all terms to the left:

-2(y-4y)+4-(-6(2y-y)+3+11y)=0

We add all the numbers together, and all the variables

-2(-3y)-(-6(+y)+3+11y)+4=0

We multiply parentheses

6y-(-6(+y)+3+11y)+4=0



We calculate terms in parentheses: -(-6(+y)+3+11y), so:

-6(+y)+3+11y

determiningTheFunctionDomain
-6(+y)+11y+3

We add all the numbers together, and all the variables

11y-6(+y)+3

We multiply parentheses

11y-6y+3

We add all the numbers together, and all the variables

5y+3

Back to the equation:

-(5y+3)



We get rid of parentheses

6y-5y-3+4=0

We add all the numbers together, and all the variables

y+1=0

We move all terms containing y to the left, all other terms to the right

y=-1

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