-2(y-5y)+2=-3(2y-y)+9+10y

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Solution for -2(y-5y)+2=-3(2y-y)+9+10y equation: 



-2(y-5y)+2=-3(2y-y)+9+10y

We move all terms to the left:

-2(y-5y)+2-(-3(2y-y)+9+10y)=0

We add all the numbers together, and all the variables

-2(-4y)-(-3(+y)+9+10y)+2=0

We multiply parentheses

8y-(-3(+y)+9+10y)+2=0



We calculate terms in parentheses: -(-3(+y)+9+10y), so:

-3(+y)+9+10y

determiningTheFunctionDomain
-3(+y)+10y+9

We add all the numbers together, and all the variables

10y-3(+y)+9

We multiply parentheses

10y-3y+9

We add all the numbers together, and all the variables

7y+9

Back to the equation:

-(7y+9)



We get rid of parentheses

8y-7y-9+2=0

We add all the numbers together, and all the variables

y-7=0

We move all terms containing y to the left, all other terms to the right

y=7

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