-2(y-5y)+5=-2(5y-y)+2+15y

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Solution for -2(y-5y)+5=-2(5y-y)+2+15y equation: 



-2(y-5y)+5=-2(5y-y)+2+15y

We move all terms to the left:

-2(y-5y)+5-(-2(5y-y)+2+15y)=0

We add all the numbers together, and all the variables

-2(-4y)-(-2(+4y)+2+15y)+5=0

We multiply parentheses

8y-(-2(+4y)+2+15y)+5=0



We calculate terms in parentheses: -(-2(+4y)+2+15y), so:

-2(+4y)+2+15y

determiningTheFunctionDomain
-2(+4y)+15y+2

We add all the numbers together, and all the variables

15y-2(+4y)+2

We multiply parentheses

15y-8y+2

We add all the numbers together, and all the variables

7y+2

Back to the equation:

-(7y+2)



We get rid of parentheses

8y-7y-2+5=0

We add all the numbers together, and all the variables

y+3=0

We move all terms containing y to the left, all other terms to the right

y=-3

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