-2(y-8)+12=27-3(y-2)

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Solution for -2(y-8)+12=27-3(y-2) equation:



-2(y-8)+12=27-3(y-2)
We move all terms to the left:
-2(y-8)+12-(27-3(y-2))=0
We multiply parentheses
-2y-(27-3(y-2))+16+12=0
We calculate terms in parentheses: -(27-3(y-2)), so:
27-3(y-2)
determiningTheFunctionDomain -3(y-2)+27
We multiply parentheses
-3y+6+27
We add all the numbers together, and all the variables
-3y+33
Back to the equation:
-(-3y+33)
We add all the numbers together, and all the variables
-2y-(-3y+33)+28=0
We get rid of parentheses
-2y+3y-33+28=0
We add all the numbers together, and all the variables
y-5=0
We move all terms containing y to the left, all other terms to the right
y=5

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