-2(z+2)-6(z+1)=98

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Solution for -2(z+2)-6(z+1)=98 equation:


Simplifying
-2(z + 2) + -6(z + 1) = 98

Reorder the terms:
-2(2 + z) + -6(z + 1) = 98
(2 * -2 + z * -2) + -6(z + 1) = 98
(-4 + -2z) + -6(z + 1) = 98

Reorder the terms:
-4 + -2z + -6(1 + z) = 98
-4 + -2z + (1 * -6 + z * -6) = 98
-4 + -2z + (-6 + -6z) = 98

Reorder the terms:
-4 + -6 + -2z + -6z = 98

Combine like terms: -4 + -6 = -10
-10 + -2z + -6z = 98

Combine like terms: -2z + -6z = -8z
-10 + -8z = 98

Solving
-10 + -8z = 98

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + -8z = 98 + 10

Combine like terms: -10 + 10 = 0
0 + -8z = 98 + 10
-8z = 98 + 10

Combine like terms: 98 + 10 = 108
-8z = 108

Divide each side by '-8'.
z = -13.5

Simplifying
z = -13.5

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