-2(z+3)-12=-2-4(z+2)

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Solution for -2(z+3)-12=-2-4(z+2) equation: 



-2(z+3)-12=-2-4(z+2)

We move all terms to the left:

-2(z+3)-12-(-2-4(z+2))=0

We multiply parentheses

-2z-(-2-4(z+2))-6-12=0



We calculate terms in parentheses: -(-2-4(z+2)), so:

-2-4(z+2)

determiningTheFunctionDomain
-4(z+2)-2

We multiply parentheses

-4z-8-2

We add all the numbers together, and all the variables

-4z-10

Back to the equation:

-(-4z-10)



We add all the numbers together, and all the variables

-2z-(-4z-10)-18=0

We get rid of parentheses

-2z+4z+10-18=0

We add all the numbers together, and all the variables

2z-8=0

We move all terms containing z to the left, all other terms to the right

2z=8

z=8/2

z=4

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