-2(z+3)-z=-z-4(z+3)

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Solution for -2(z+3)-z=-z-4(z+3) equation: 



-2(z+3)-z=-z-4(z+3)

We move all terms to the left:

-2(z+3)-z-(-z-4(z+3))=0

We add all the numbers together, and all the variables

-1z-2(z+3)-(-z-4(z+3))=0

We multiply parentheses

-1z-2z-(-z-4(z+3))-6=0



We calculate terms in parentheses: -(-z-4(z+3)), so:

-z-4(z+3)

We add all the numbers together, and all the variables

-1z-4(z+3)

We multiply parentheses

-1z-4z-12

We add all the numbers together, and all the variables

-5z-12

Back to the equation:

-(-5z-12)



We add all the numbers together, and all the variables

-3z-(-5z-12)-6=0

We get rid of parentheses

-3z+5z+12-6=0

We add all the numbers together, and all the variables

2z+6=0

We move all terms containing z to the left, all other terms to the right

2z=-6

z=-6/2

z=-3

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