-2(z+3)-z=z-4(z+4)

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Solution for -2(z+3)-z=z-4(z+4) equation: 



-2(z+3)-z=z-4(z+4)

We move all terms to the left:

-2(z+3)-z-(z-4(z+4))=0

We add all the numbers together, and all the variables

-1z-2(z+3)-(z-4(z+4))=0

We multiply parentheses

-1z-2z-(z-4(z+4))-6=0



We calculate terms in parentheses: -(z-4(z+4)), so:

z-4(z+4)

We multiply parentheses

z-4z-16

We add all the numbers together, and all the variables

-3z-16

Back to the equation:

-(-3z-16)



We add all the numbers together, and all the variables

-3z-(-3z-16)-6=0

We get rid of parentheses

-3z+3z+16-6=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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