-2+(3y-4)/4=2y-3

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Solution for -2+(3y-4)/4=2y-3 equation: 



-2+(3y-4)/4=2y-3

We move all terms to the left:

-2+(3y-4)/4-(2y-3)=0

We get rid of parentheses

(3y-4)/4-2y+3-2=0

We multiply all the terms by the denominator


(3y-4)-2y*4+3*4-2*4=0

We add all the numbers together, and all the variables

(3y-4)-2y*4+4=0

Wy multiply elements

(3y-4)-8y+4=0

We get rid of parentheses

3y-8y-4+4=0

We add all the numbers together, and all the variables

-5y=0

y=0/-5

y=0

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