-2+-9y+18y2=0

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Solution for -2+-9y+18y2=0 equation:



-2+-9y+18y^2=0
We add all the numbers together, and all the variables
18y^2-9y=0
a = 18; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·18·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*18}=\frac{0}{36} =0 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*18}=\frac{18}{36} =1/2 $

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