If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-2+-9y+18y^2=0
We add all the numbers together, and all the variables
18y^2-9y=0
a = 18; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·18·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*18}=\frac{0}{36} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*18}=\frac{18}{36} =1/2 $
| -5(x-6=-6(4-x) | | 4(2x-1)=50 | | 5m+7=32m= | | -5+12x=13x+7 | | 6w+3w-3=17 | | x/5-4-4=x/3 | | 8x+1=-3-x | | 4x+6+1=20 | | 5x(8x-11)=(2x+6) | | -5(-2x+5)-2x=2(x-3)-4 | | 2(2x+3)+1=20 | | 1/2x-9=9+5/4x | | -2(2-r)=8 | | 2/3n+-5/3=n/6+1/3 | | (8x-11)+(2x+6)=5x | | 6x+30=9x+3 | | 8x-6=7x=4 | | x/8+5=- | | z/9+1=9 | | (⅔x+10)=(15)(x/5+36/5) | | 5x+33=9x+9 | | 7x+3=4x+20 | | h9=8 | | 7p(3p+4)=2(2p-1)+10 | | -4(5-8x)-2x=130 | | x/9+4=59 | | 12x=36x | | 3y+2=-10y+30 | | 7/5v=-42 | | -7-2k-3k=0 | | 6x+12=12+6 | | a/4+$=10 |