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-2+1/10x=7-4/5x
We move all terms to the left:
-2+1/10x-(7-4/5x)=0
Domain of the equation: 10x!=0
x!=0/10
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/10x-(-4/5x+7)-2=0
We get rid of parentheses
1/10x+4/5x-7-2=0
We calculate fractions
5x/50x^2+40x/50x^2-7-2=0
We add all the numbers together, and all the variables
5x/50x^2+40x/50x^2-9=0
We multiply all the terms by the denominator
5x+40x-9*50x^2=0
We add all the numbers together, and all the variables
45x-9*50x^2=0
Wy multiply elements
-450x^2+45x=0
a = -450; b = 45; c = 0;
Δ = b2-4ac
Δ = 452-4·(-450)·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-45}{2*-450}=\frac{-90}{-900} =1/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+45}{2*-450}=\frac{0}{-900} =0 $
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