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-2+3x=x-2(1+2x)
We move all terms to the left:
-2+3x-(x-2(1+2x))=0
We add all the numbers together, and all the variables
3x-(x-2(2x+1))-2=0
We calculate terms in parentheses: -(x-2(2x+1)), so:We get rid of parentheses
x-2(2x+1)
We multiply parentheses
x-4x-2
We add all the numbers together, and all the variables
-3x-2
Back to the equation:
-(-3x-2)
3x+3x+2-2=0
We add all the numbers together, and all the variables
6x=0
x=0/6
x=0
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