-2+4w2=w

Solution for -2+4w2=w equation:

-2+4w^2=w

We move all terms to the left:

-2+4w^2-(w)=0

We add all the numbers together, and all the variables

4w^2-1w-2=0

a = 4; b = -1; c = -2;
Δ = b2-4ac
Δ = -12-4·4·(-2)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{33}}{2*4}=\frac{1-\sqrt{33}}{8}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{33}}{2*4}=\frac{1+\sqrt{33}}{8}
$