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-2+5(5x-2)=-5-5(5x-7)
We move all terms to the left:
-2+5(5x-2)-(-5-5(5x-7))=0
We multiply parentheses
25x-(-5-5(5x-7))-10-2=0
We calculate terms in parentheses: -(-5-5(5x-7)), so:We add all the numbers together, and all the variables
-5-5(5x-7)
determiningTheFunctionDomain -5(5x-7)-5
We multiply parentheses
-25x+35-5
We add all the numbers together, and all the variables
-25x+30
Back to the equation:
-(-25x+30)
25x-(-25x+30)-12=0
We get rid of parentheses
25x+25x-30-12=0
We add all the numbers together, and all the variables
50x-42=0
We move all terms containing x to the left, all other terms to the right
50x=42
x=42/50
x=21/25
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