-2+6(x+2)=1-3(x-5)+3x

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Solution for -2+6(x+2)=1-3(x-5)+3x equation:



-2+6(x+2)=1-3(x-5)+3x
We move all terms to the left:
-2+6(x+2)-(1-3(x-5)+3x)=0
We multiply parentheses
6x-(1-3(x-5)+3x)+12-2=0
We calculate terms in parentheses: -(1-3(x-5)+3x), so:
1-3(x-5)+3x
determiningTheFunctionDomain -3(x-5)+3x+1
We add all the numbers together, and all the variables
3x-3(x-5)+1
We multiply parentheses
3x-3x+15+1
We add all the numbers together, and all the variables
16
Back to the equation:
-(16)
We add all the numbers together, and all the variables
6x-6=0
We move all terms containing x to the left, all other terms to the right
6x=6
x=6/6
x=1

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