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-2.5x^2+5x-1.9=0
a = -2.5; b = 5; c = -1.9;
Δ = b2-4ac
Δ = 52-4·(-2.5)·(-1.9)
Δ = 6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{6}}{2*-2.5}=\frac{-5-\sqrt{6}}{-5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{6}}{2*-2.5}=\frac{-5+\sqrt{6}}{-5} $
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