-2-3(y-6)=5(4y-2)-7

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Solution for -2-3(y-6)=5(4y-2)-7 equation:



-2-3(y-6)=5(4y-2)-7
We move all terms to the left:
-2-3(y-6)-(5(4y-2)-7)=0
We multiply parentheses
-3y-(5(4y-2)-7)+18-2=0
We calculate terms in parentheses: -(5(4y-2)-7), so:
5(4y-2)-7
We multiply parentheses
20y-10-7
We add all the numbers together, and all the variables
20y-17
Back to the equation:
-(20y-17)
We add all the numbers together, and all the variables
-3y-(20y-17)+16=0
We get rid of parentheses
-3y-20y+17+16=0
We add all the numbers together, and all the variables
-23y+33=0
We move all terms containing y to the left, all other terms to the right
-23y=-33
y=-33/-23
y=1+10/23

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