-2-3(y-6)=5(4y-2)-7

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Solution for -2-3(y-6)=5(4y-2)-7 equation: 



-2-3(y-6)=5(4y-2)-7

We move all terms to the left:

-2-3(y-6)-(5(4y-2)-7)=0

We multiply parentheses

-3y-(5(4y-2)-7)+18-2=0



We calculate terms in parentheses: -(5(4y-2)-7), so:

5(4y-2)-7

We multiply parentheses

20y-10-7

We add all the numbers together, and all the variables

20y-17

Back to the equation:

-(20y-17)



We add all the numbers together, and all the variables

-3y-(20y-17)+16=0

We get rid of parentheses

-3y-20y+17+16=0

We add all the numbers together, and all the variables

-23y+33=0

We move all terms containing y to the left, all other terms to the right

-23y=-33

y=-33/-23

y=1+10/23

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