-2-5(4r-2)=128

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Solution for -2-5(4r-2)=128 equation: 



-2-5(4r-2)=128

We move all terms to the left:

-2-5(4r-2)-(128)=0

We add all the numbers together, and all the variables

-5(4r-2)-130=0

We multiply parentheses

-20r+10-130=0

We add all the numbers together, and all the variables

-20r-120=0

We move all terms containing r to the left, all other terms to the right

-20r=120

r=120/-20

r=-6

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