-2-5=2-4x(x-1)

Solution for -2-5=2-4x(x-1) equation:

-2-5=2-4x(x-1)

We move all terms to the left:

-2-5-(2-4x(x-1))=0

We add all the numbers together, and all the variables

-(2-4x(x-1))-7=0


We calculate terms in parentheses: -(2-4x(x-1)), so:

2-4x(x-1)

determiningTheFunctionDomain
-4x(x-1)+2

We multiply parentheses

-4x^2+4x+2

Back to the equation:

-(-4x^2+4x+2)


We get rid of parentheses

4x^2-4x-2-7=0

We add all the numbers together, and all the variables

4x^2-4x-9=0

a = 4; b = -4; c = -9;
Δ = b2-4ac
Δ = -42-4·4·(-9)
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{10}}{2*4}=\frac{4-4\sqrt{10}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{10}}{2*4}=\frac{4+4\sqrt{10}}{8}
$