-2-5i/3i

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Solution for -2-5i/3i equation:


i in (-oo:+oo)

-(((5*i)/3)*i)-2 = 0

(-5/3)*i^2-2 = 0

-5/3*i^2 = 2 // : -5/3

i^2 = -6/5

i belongs to the empty set

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