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-2/2y=2/y-15
We move all terms to the left:
-2/2y-(2/y-15)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: y-15)!=0We get rid of parentheses
y∈R
-2/2y-2/y+15=0
We calculate fractions
(-2y)/2y^2+(-4y)/2y^2+15=0
We multiply all the terms by the denominator
(-2y)+(-4y)+15*2y^2=0
Wy multiply elements
30y^2+(-2y)+(-4y)=0
We get rid of parentheses
30y^2-2y-4y=0
We add all the numbers together, and all the variables
30y^2-6y=0
a = 30; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·30·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*30}=\frac{0}{60} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*30}=\frac{12}{60} =1/5 $
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