-2/3(-3y+3)+3y=-33

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Solution for -2/3(-3y+3)+3y=-33 equation: 



-2/3(-3y+3)+3y=-33

We move all terms to the left:

-2/3(-3y+3)+3y-(-33)=0



Domain of the equation: 3(-3y+3)!=0

y∈R



We add all the numbers together, and all the variables

3y-2/3(-3y+3)+33=0

We multiply all the terms by the denominator


3y*3(-3y+3)+33*3(-3y+3)-2=0

Wy multiply elements

9y^2(-+99y(--2=0

We use the square of the difference formula

9y^2(-99y(+2=0

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