-2/3(15c-24)=4/9(18-27c)

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Solution for -2/3(15c-24)=4/9(18-27c) equation: 



-2/3(15c-24)=4/9(18-27c)

We move all terms to the left:

-2/3(15c-24)-(4/9(18-27c))=0



Domain of the equation: 3(15c-24)!=0

c∈R





Domain of the equation: 9(18-27c))!=0

c∈R



We add all the numbers together, and all the variables

-2/3(15c-24)-(4/9(-27c+18))=0

We calculate fractions


(-18c(-)/(3(15c-24)*9(-27c+18)))+(-12c1/(3(15c-24)*9(-27c+18)))=0



We calculate terms in parentheses: +(-18c(-)/(3(15c-24)*9(-27c+18))), so:

-18c(-)/(3(15c-24)*9(-27c+18))

We add all the numbers together, and all the variables

-18c0/(3(15c-24)*9(-27c+18))

We multiply all the terms by the denominator


-18c0

We add all the numbers together, and all the variables

-18c

Back to the equation:

+(-18c)





We calculate terms in parentheses: +(-12c1/(3(15c-24)*9(-27c+18))), so:

-12c1/(3(15c-24)*9(-27c+18))

We multiply all the terms by the denominator


-12c1

We add all the numbers together, and all the variables

-12c

Back to the equation:

+(-12c)



We get rid of parentheses

-18c-12c=0

We add all the numbers together, and all the variables

-30c=0

c=0/-30

c=0

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