-2/3(k+3)=12

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Solution for -2/3(k+3)=12 equation: 



-2/3(k+3)=12

We move all terms to the left:

-2/3(k+3)-(12)=0



Domain of the equation: 3(k+3)!=0

k∈R



We multiply all the terms by the denominator


-12*3(k+3)-2=0

Wy multiply elements

-36k(k-2=0

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