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-2/3(x+1)=1/2(2-x)
We move all terms to the left:
-2/3(x+1)-(1/2(2-x))=0
Domain of the equation: 3(x+1)!=0
x∈R
Domain of the equation: 2(2-x))!=0We add all the numbers together, and all the variables
x∈R
-2/3(x+1)-(1/2(-1x+2))=0
We calculate fractions
(-4x(-)/(3(x+1)*2(-1x+2)))+(-3xx/(3(x+1)*2(-1x+2)))=0
We calculate terms in parentheses: +(-4x(-)/(3(x+1)*2(-1x+2))), so:
-4x(-)/(3(x+1)*2(-1x+2))
We add all the numbers together, and all the variables
-4x0/(3(x+1)*2(-1x+2))
We multiply all the terms by the denominator
-4x0
We add all the numbers together, and all the variables
-4x
Back to the equation:
+(-4x)
We calculate terms in parentheses: +(-3xx/(3(x+1)*2(-1x+2))), so:We get rid of parentheses
-3xx/(3(x+1)*2(-1x+2))
We multiply all the terms by the denominator
-3xx
Back to the equation:
+(-3xx)
-4x-3xx=0
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