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-2/3(x+12)+2/3=-5/4x+2
We move all terms to the left:
-2/3(x+12)+2/3-(-5/4x+2)=0
Domain of the equation: 3(x+12)!=0
x∈R
Domain of the equation: 4x+2)!=0We get rid of parentheses
x∈R
-2/3(x+12)+5/4x-2+2/3=0
We calculate fractions
(-8x)/(3(x+12)*4x*3)+(45xx/(3(x+12)*4x*3)+8x/(3(x+12)*4x*3)-2=0
We calculate terms in parentheses: +(-8x)/(3(x+12)*4x*3), so:We multiply all the terms by the denominator
-8x)/(3(x+12)*4x*3
We multiply all the terms by the denominator
-8x)
Back to the equation:
+(-8x))
(-8x))+(45xx+8x-2*(3(x+12)*4x*3)=0
We add all the numbers together, and all the variables
8x+(-8x))+(45xx-2*(3(x+12)*4x*3)=0
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