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-2/3(x+12)x=-5/4x+2
We move all terms to the left:
-2/3(x+12)x-(-5/4x+2)=0
Domain of the equation: 3(x+12)x!=0
x∈R
Domain of the equation: 4x+2)!=0We get rid of parentheses
x∈R
-2/3(x+12)x+5/4x-2=0
We calculate fractions
(-8x)/(3(x+12)x*4x)+(15xx/(3(x+12)x*4x)-2=0
We calculate terms in parentheses: +(-8x)/(3(x+12)x*4x), so:We multiply all the terms by the denominator
-8x)/(3(x+12)x*4x
We multiply all the terms by the denominator
-8x)
Back to the equation:
+(-8x))
(-8x))+(15xx-2*(3(x+12)x*4x)=0
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