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-2/3(x+2)=1/6(x-6)
We move all terms to the left:
-2/3(x+2)-(1/6(x-6))=0
Domain of the equation: 3(x+2)!=0
x∈R
Domain of the equation: 6(x-6))!=0We calculate fractions
x∈R
(-12xx/(3(x+2)*6(x-6)))+(-3xx/(3(x+2)*6(x-6)))=0
We calculate terms in parentheses: +(-12xx/(3(x+2)*6(x-6))), so:
-12xx/(3(x+2)*6(x-6))
We multiply all the terms by the denominator
-12xx
Back to the equation:
+(-12xx)
We calculate terms in parentheses: +(-3xx/(3(x+2)*6(x-6))), so:We get rid of parentheses
-3xx/(3(x+2)*6(x-6))
We multiply all the terms by the denominator
-3xx
Back to the equation:
+(-3xx)
-12xx-3xx=0
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