-2/3(x-2)=1/6(x+6)

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Solution for -2/3(x-2)=1/6(x+6) equation: 



-2/3(x-2)=1/6(x+6)

We move all terms to the left:

-2/3(x-2)-(1/6(x+6))=0



Domain of the equation: 3(x-2)!=0

x∈R





Domain of the equation: 6(x+6))!=0

x∈R



We calculate fractions


(-12xx/(3(x-2)*6(x+6)))+(-3xx/(3(x-2)*6(x+6)))=0



We calculate terms in parentheses: +(-12xx/(3(x-2)*6(x+6))), so:

-12xx/(3(x-2)*6(x+6))

We multiply all the terms by the denominator


-12xx

Back to the equation:

+(-12xx)





We calculate terms in parentheses: +(-3xx/(3(x-2)*6(x+6))), so:

-3xx/(3(x-2)*6(x+6))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)



We get rid of parentheses

-12xx-3xx=0

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