-2/3(x-7)=1/6(x+1)-3

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Solution for -2/3(x-7)=1/6(x+1)-3 equation: 



-2/3(x-7)=1/6(x+1)-3

We move all terms to the left:

-2/3(x-7)-(1/6(x+1)-3)=0



Domain of the equation: 3(x-7)!=0

x∈R





Domain of the equation: 6(x+1)-3)!=0

x∈R



We calculate fractions


(-12xx/(3(x-7)*6(x+1))+(-3xx/(3(x-7)*6(x+1))=0



We calculate terms in parentheses: +(-12xx/(3(x-7)*6(x+1))+(-3xx/(3(x-7)*6(x+1)), so:

-12xx/(3(x-7)*6(x+1))+(-3xx/(3(x-7)*6(x+1)

We calculate fractions


(-12xx*(3(x-7)*6(x+1))/((3(x-7)*6(x+1))*(3(x-7)*6(x+1))+((-3xx*(3(x-7)*6(x+1)))/((3(x-7)*6(x+1))*(3(x-7)*6(x+1))



We calculate terms in parentheses: +(-12xx*(3(x-7)*6(x+1))/((3(x-7)*6(x+1))*(3(x-7)*6(x+1))+((-3xx*(3(x-7)*6(x+1)))/((3(x-7)*6(x+1))*(3(x-7)*6(x+1)), so:

-12xx*(3(x-7)*6(x+1))/((3(x-7)*6(x+1))*(3(x-7)*6(x+1))+((-3xx*(3(x-7)*6(x+1)))/((3(x-7)*6(x+1))*(3(x-7)*6(x+1)

We can not solve this equation

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