-2/3(z+3)=-3/8(z+5)

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Solution for -2/3(z+3)=-3/8(z+5) equation: 



-2/3(z+3)=-3/8(z+5)

We move all terms to the left:

-2/3(z+3)-(-3/8(z+5))=0



Domain of the equation: 3(z+3)!=0

z∈R





Domain of the equation: 8(z+5))!=0

z∈R



We calculate fractions


(-16zz/(3(z+3)*8(z+5)))+(-(-9zz)/(3(z+3)*8(z+5)))=0



We calculate terms in parentheses: +(-16zz/(3(z+3)*8(z+5))), so:

-16zz/(3(z+3)*8(z+5))

We multiply all the terms by the denominator


-16zz

Back to the equation:

+(-16zz)





We calculate terms in parentheses: +(-(-9zz)/(3(z+3)*8(z+5))), so:

-(-9zz)/(3(z+3)*8(z+5))

We multiply all the terms by the denominator


-(-9zz)

We get rid of parentheses

9zz

Back to the equation:

+(9zz)



We get rid of parentheses

-16zz+9zz=0

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