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-2/3+2g=-3/2g+3-2g
We move all terms to the left:
-2/3+2g-(-3/2g+3-2g)=0
Domain of the equation: 2g+3-2g)!=0We add all the numbers together, and all the variables
We move all terms containing g to the left, all other terms to the right
2g-2g)!=-3
g∈R
2g-(-2g-3/2g+3)-2/3=0
We get rid of parentheses
2g+2g+3/2g-3-2/3=0
We calculate fractions
There is no solution for this equation
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