-2/3=1/6(n+12)

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Solution for -2/3=1/6(n+12) equation: 



-2/3=1/6(n+12)

We move all terms to the left:

-2/3-(1/6(n+12))=0



Domain of the equation: 6(n+12))!=0

n∈R



We calculate fractions


()/18n+(-12nn/18n=0

We multiply all the terms by the denominator


(-12nn+()=0



We calculate terms in parentheses: +(-12nn+(), so:

-12nn+(

We add all the numbers together, and all the variables

-12nn

Back to the equation:

+(-12nn)



We get rid of parentheses

-12nn=0

n=0/1

n=0

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