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-2/3m-1/6m=-5
We move all terms to the left:
-2/3m-1/6m-(-5)=0
Domain of the equation: 3m!=0
m!=0/3
m!=0
m∈R
Domain of the equation: 6m!=0We add all the numbers together, and all the variables
m!=0/6
m!=0
m∈R
-2/3m-1/6m+5=0
We calculate fractions
(-12m)/18m^2+(-3m)/18m^2+5=0
We multiply all the terms by the denominator
(-12m)+(-3m)+5*18m^2=0
Wy multiply elements
90m^2+(-12m)+(-3m)=0
We get rid of parentheses
90m^2-12m-3m=0
We add all the numbers together, and all the variables
90m^2-15m=0
a = 90; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·90·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*90}=\frac{0}{180} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*90}=\frac{30}{180} =1/6 $
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