-2/3p+3/2p=-71/12

Solution for -2/3p+3/2p=-71/12 equation:

-2/3p+3/2p=-71/12

We move all terms to the left:

-2/3p+3/2p-(-71/12)=0


Domain of the equation: 3p!=0

p!=0/3

p!=0

p∈R



Domain of the equation: 2p!=0

p!=0/2

p!=0

p∈R


We get rid of parentheses

-2/3p+3/2p+71/12=0

We calculate fractions


852p^2/72p^2+(-48p)/72p^2+108p/72p^2=0

We multiply all the terms by the denominator


852p^2+(-48p)+108p=0

We add all the numbers together, and all the variables

852p^2+108p+(-48p)=0

We get rid of parentheses

852p^2+108p-48p=0

We add all the numbers together, and all the variables

852p^2+60p=0

a = 852; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·852·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*852}=\frac{-120}{1704}
=-5/71
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*852}=\frac{0}{1704}
=0
$