-2/3x+(-x)=6

Solution for -2/3x+(-x)=6 equation:

-2/3x+(-x)=6

We move all terms to the left:

-2/3x+(-x)-(6)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

-2/3x+(-1x)-6=0

We get rid of parentheses

-2/3x-1x-6=0

We multiply all the terms by the denominator


-1x*3x-6*3x-2=0

Wy multiply elements

-3x^2-18x-2=0

a = -3; b = -18; c = -2;
Δ = b2-4ac
Δ = -182-4·(-3)·(-2)
Δ = 300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{300}=\sqrt{100*3}=\sqrt{100}*\sqrt{3}=10\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-10\sqrt{3}}{2*-3}=\frac{18-10\sqrt{3}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+10\sqrt{3}}{2*-3}=\frac{18+10\sqrt{3}}{-6}
$